Time Speed and Distance Doubts
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As we know that AP = a+(n-1) d
In the qus 4 why there is written 12/2 and 35×2 why we have to multiply with 2 .. Becoz that's not the same as formula.
Posted : 02/08/2022 11:31 am
Hi Sneha,
here we see that the total distance travelled in 12 hours = 35 + 37 + 39 +...upto 12 terms.
this is nothing but an Ap with first term(a) = 35 and common difference(d) = 37-37 = 2
hence we are required to find the sum of the AP up to 12 terms.
formula to find the sum of AP up to n terms with the first term(a) and common difference (d) = [n/2(2a+(n-1)d)]
Hence the required distance = [12/2(2*35+(12-1)*2] = [6(70 +11*2)] = 6(70+22) = 552 kms
I hope this was helpful for you.
Happy learning!
Posted : 23/08/2022 8:24 pm
